Prime

If n4+4n.then number of values of n,nEN is

5 Answers

11
Joydoot ghatak ·

do u mean,
If n4+4n is prime, then number of values of n,nEN is...???

1
Ricky ·

Lemma : -

If " n " is odd , then " 2 n - 2 " can be written down as " 4 k " , where " k " ( ≥ 0 ) E { I } .

Proof : -

If " n " is odd , then " n - 1 " must be even , i.e , " n - 1 " is of the form " 2 k " .

Hence , " 2 ( n - 1 ) " or " 2 n - 2 " is of the form " 4 k " .

11
Joydoot ghatak ·

@ricky,
how does this help here.. :(

in this problem, i can see only that n can not take even values..
and n=1 gives a prime number...

1
Vinay Arya ·

Yes Joydoot,I mean that.Sorry for mistyping.
Please help me.

1
Ricky ·

Sorry , I now finish my proof .

If " n " be odd , then let " 2 n - 2 = 4 k " .

Now ,

n 4 + 4 n = n 4 + 4 . 2 2 n - 2 = ( n 2 + 2 . n . 2 k + 2 2 k ) ( n 2 - 2 . n . 2 k + 2 2 k )

Since we can factorise the given expression , therefore it cannot be a prime .

We didn't consider the case " n = 1 " , for which value only the expression generates a prime number , " 5 " .

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