Algebra - probaaaaability

39

Dr.House ·2009-02-19 09:04:10

total outcomes is 3 na.

do u want total number of possible outcomes?

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big looser ......... ·2009-02-19 09:08:10

ya

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39

Dr.House ·2009-02-19 09:09:25

18P₃/6!.6!.6!

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1

big looser ......... ·2009-02-19 09:12:32

y u hve divided by (6!)³

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big looser ......... ·2009-02-19 09:16:13

answer is 216. ur answer is not an integer

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1

MATRIX ·2009-02-19 09:17:01

is it 216..........may be for iit........

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big looser ......... ·2009-02-19 09:18:09

plz explain

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39

Dr.House ·2009-02-19 09:19:51

first one there can be 6 outcomes and for secind one there can be 6 and for third one there can be 6

so total possible is 6.6.6=216

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1

MATRIX ·2009-02-19 09:20:29

simply 6³=216...........

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1

big looser ......... ·2009-02-19 09:24:16

but (1,1,1) will be counted as 3 times

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1

MATRIX ·2009-02-19 09:28:05

hw may be.......????

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big looser ......... ·2009-02-19 09:33:40

sorry

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24

eureka123 ·2009-02-19 10:30:32

since all 3 events are independent so no. of ways=6*6*6=216....[1][1]

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62

Lokesh Verma ·2009-02-19 21:47:12

@aman.. 1,1,1 is counted only once..

Think again :)

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