A ball is drawn at random from a bag containing 3 balls and it is found to be black. If it is equally likely that it may contain 1 or 2 or 3 black balls, the probability that the ball drawn is the only black ball is...is the ans 1/3?
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1 Answers
62P(\text{Drawn ball is the only black ball }\mid\text{ A black ball is drawn}) = P(\text{Drawn ball is the only black ball }\bigcap{}\text{A black ball is drawn})/P\text{Black ball drawn}
Now can you solve?