1wat s wrong in 1
Q.1
TWO DICES ARE THROWN SIMULTANEOUSLY.THE PROBABILITY OF OBTAINING A TOTAL SCORE LESS THAN 11??
Q.2
SIX DICES ARE THROWN AT ONCE THEN PROBABILITY THAT ALL SIX DICES SHOW DIFFERENT FACES IS???
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17 Answers
62I think richa you have done some hadbadi..
for 1st dice any no possible so p(1)=1(say 4)
for 2nd dice any no except 4 will do so p(2)=5/6
p(3)=5/6 n so on
p total=p1*p2*p3*p4*p5*p6
1x5/6x4/6x3/6x2/6x1/6
= 5.4.3.2/ 65
= 5.4/ 64
= 5/(324)
1for 1st dice any no possible so p(1)=1(say 4) for 2nd dice any no except 4 will do so p(2)=5/6 p(3)=4/6 n so on p total=p1*p2*p3*p4*p5*p6
62pavan.. 1 is right
probability is (36-3)/36
no of ways to get 12 is 1
no of ways to get 11 is 2
total no of ways is 36
hence the above answer
1total cases -3(getting 11 or12)
possible outcomes 36
favourable outcomes 33