probability

Three numbers are chosen at random from 1 to 20. The probability that they are consecutive is

47 Answers

11
vaibhav sharma ·

karm karo phal ki ichha mat karo

1
gordo ·

try solving for the numbers to be in a.p
revised question: probability of the 3 numbers being in ap.
nice one.

11
vaibhav sharma ·

@gordo

for a.p. probability:

P(required) = (18+8+5+3+2+2+1+1+1)/(20c3)
ans= 41/190

1
souvik seal ·

coolrocks has given aright solution

11
vaibhav sharma ·

try these :

LEVEL I:

Q1. 10 NO'S ARE CHOSEN FROM AMONG THE NO'S 1-100 AND ARRANGED IN INCREASING ORDER . FIND THE PROBABILITY THAT 45 IS THE 5TH NO FROM LEFT IN THIS ORDER (REMEMBER THE ARRANGEMENT IS DONE IN INCREASING ORDER).

LEVEL II:

Q2. A WIRE OF LENGTH L IS CUT INTO THREE PIECES . FIND PROBABILITY THAT THESE PIECES FORM A TRIANGLE

LEVEL III: (NOT REALLY A LEVEL III QUESTION ...DEPENDS ON YOUR COMMON SENSE)

Q3. TWO CARDS ARE DRAWN FROM A PACK OF CARDS (A 52 CARD DECK).FIND PROBABILITY THAT ONE CARD IS HEART AND OTHER IS ACE.

1
ronak agarwal ·

for A.P probability question:
P(required)=(18+16+14+12+10+8+6+4+2)/(20C3)
=90/20c3

1
akash_kumar ·

I think it's simply Ans=3-120=220=110y

1
ronak agarwal ·

Level 1 ans:
(44C4/100C10)*(1/46)

1
ronak agarwal ·

Level 3 ans:
probability of getting a heart or an ace=(13+3)/52=16/52=4/13

11
vaibhav sharma ·

there some mistake in a.p. answer i gave the correct answer would be:

P(required)=(18+16+10+6+4+4+2+2+2)/(20c3)
= 64/190
=32/95

11
vaibhav sharma ·

@ronak

ur level one question's answer maybe right( i dont know the answer)

but ur level 3 question's answer is wrong

11
vaibhav sharma ·

@ronak

in 3rd question u did the mistake what everyone does

1
ronak agarwal ·

oh sry i didn't c v had to draw two cards...

1
ronak agarwal ·

Level 3 ans:
16c2/52c2
=20/221

11
vaibhav sharma ·

@ronak
no

1
arkadipta sarkar ·

is the ans
13C1/52C1*13C1/52C1
=1/16???

11
vaibhav sharma ·

@arkadipta
no

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