p = 6/6x6 = 1/6........
=> 648p = 108........
here d reading 1,2 is diff from 2,1...
:)
two persons ach make a thrw wid a pair of cubical die n let p denote d prob dat their thrws r equal
then find d value of 648p
Given by Integrations!
p = 6/6x6 = 1/6........
=> 648p = 108........
here d reading 1,2 is diff from 2,1...
:)
91
@ram n MAK
they each made a throw with a pair of cubical die
DOES D Q MEAN LIK DAT????????????????
IF SO I M SRRY.......[2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2][2]
sum of
the
two no. probobility of getting by both
2 1/64
3 22/64
4 32/64
5 42/64
6 52/64
7 62/64
8 52/64
9 42/64
10 32/64
11 22/64
12 1/64
required probability=2/64*[12+22+32...+62]
p=91/648
ans=91
I think abhirup you have made a small mistake!!
probab of getting upto 6 seems correct..
then it will be different from what you have got!
sorry i made a mistake in copy paste....
plz check it now.....