nCp*(x)^p(y)^[n-p] .....
may be rong guess at first sight ... [3]
Let A and B be two events such that B=A and p(A) = x and p(B) = y. Let the actual event be T.
Let the event T be carried out n times. What is the probability that A occurs exactly p times (p<n)?
see we have to have A occuring p times ..... and every time P is carries out its independent of the previous results .......
also we can select the times we want a to occur outta the n times ....
and the remainin trials have to be all givin b as result ,,,
so we have ...
nCp (x)^p (y)^(n-p) ,.....