Let ABC be a triangle , O the center of circumcircle and BB' a diameter.
Let's try and find out the probability that it is an acute angled triangle.(Since it involves less complications)
If ABC is acute angled then O will be included inside ΔABC.
(Using normal coordinate system with center as origin)For ΔABC to be acute A should lie in 2nd quadrant and C should lie in 3rd quadrant.
Hence probability that ΔABC is acute = 1/2*/12=1/4
Therefore probability that the triangle is obtuse = 3/4
- Manish Shankar good work :)Upvote·0· Reply ·2013-10-17 22:39:14