Four fair dice D1, D2, D3 and D4, each having six faces numbered 1, 2, 3, 4, 5, and 6, are rolled
simultaneously. The probability that D4 shows a number appearing on one of D1, D2 and D3 is
(A) 91/216
(B) 108/216
(C) 125/216
(D) 127/216
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2 Answers
Shaswata Roy
·2013-02-22 08:58:49
Ans -(b) 108/216
- Hardik Sheth can u plz explain..?Upvote·0· Reply ·2013-02-22 09:02:42
- Shaswata Roy Yeah it's (a)91/216
- Shaswata Roy Sorry,my bad.
- Soumyadeep Basu Is it (b) even if D1, D2 and D3 do not all show different numbers?
- Hardik Sheth i dint get you
- Soumyadeep Basu It's ok. I've solved it.