probablilyti

nobodie??

c 121 ?

two ways .. either take n as 4 ... or use binomial method !

if u take n=4, wat will u get as p2,p1 think yaar!!

0 aega!!!

from where did you get this question????????????????

p_n=ⁿC₂(3/4)²(1/4)^n-2+ⁿC₁(3/4)(1/4)^n-1

CONSECUTIVVELY

i think u missd that

oops...i missed that.....

pls find my fault,,,i am getting 34?????

p_n = (1-p)p_n-1 + p(1-p)p_n-2 + 2p(1-p)²p_n-3
......p=3/4, 1-p=1/4
thus we get 64(α+β+γ)=34 !!!!!!!!!!
....where am i wrong ?

hey someone clear my doubt....i am not getting the same answer !