Probablitty again

A random point is unifomly distributed in a square of side length 1 unit.
Q1 Find probablity thta distance of A from nearest side doesnt exceed x (x<1/√2)
Q2 Find probablity thta distance of A from centre does not exceed x (x<1/√2)
Q3 Find probablity thta distance of A from fixed vertex of square does not exceed x(x<√2)

12 Answers

62
Lokesh Verma ·

This i sby taking the area...

For example part 2, the area of all x such that x<1/√2 = pi/2 but this whole area is covered by the square...

answer is 1

Q3, the answer is 1 because the whole square will be taken by the distance √2

Same with question 1..

so all answers are 1

24
eureka123 ·

no sir

answers are really wierd

1
Philip Calvert ·

I think answers are wanted in terms of x

1357
Manish Shankar ·

Q1
(1-2x)2 for 0<x<1/2
1 for 1/2≤x<1/√2

Is this the answer

24
eureka123 ·

no

plzzzzzzzzzzzzz help..should I post the answer and then everyoen can post the soln ?

24
eureka123 ·

???

1
gagar.iitk ·

ans q1 4 x(1-x) for 0<x<1/2

11
Devil ·

http://www.goiit.com/posts/list/algebra-try-this-909198.htm
This may help.

62
Lokesh Verma ·

see I misread the question grossly... i think soumik's link gives the proof nicely... but still if you want i will post it again...

i solved it using x= in each of these...

so lets see for any arbitrary x...
Part 1:

Area of unshaded region is 1-(1-2x)2 which will give the probability...

(I hope i am not overlooking anythign this time :P )

62
Lokesh Verma ·

In the 2nd quesiton there will be 2 cases.. one when radius is less than 1/2

2nd when it will be greater than 1/2 but less than 1/√2

Now use these figures...

24
eureka123 ·

I am giving the answers sir here...now post the soln...

1)4x(1-x)
2)Ï€x2+√4x2-1-4x2tan-14x2-1
3)Ï€x24-x2tan-1x2x2-1+√x2-1

62
Lokesh Verma ·

again in the next part there will be 2 parts...

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