no of elements in m = 6 and n = 3
Two finite sets have m and n elements. The total number of subsets of the first set is 56 more than the total number of subsets of the second set. Find the value of m and n.
This is a qestion from fiitjee s material. Mobile se pucha hai. So pls work it out.
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6 Answers
It's clear that the first set has 2m subsets and second one has 2n subests.
so we have to solve 2m - 2n = 56 (m,n are positive integers)
Its also clear that m>n
let m = k+n
so 2k+n- 2n= 56
2n(2k- 1)= 23*7
clearly 2k-1 is odd
so 2n= 23, and n = 3
and 2k-1= 7 so k =3
so m = 3+3 = 6 and n = 3
;O)
Thanks shubhodip bhai! I worked it out by hit and trial method but ur's have some logic.
hit and trial se ho gaya na!!
bas theek hai!!
:P
but good job shubhodip....:)