Please help!!
any genius out there?
The question is
Prove that
1 + 1/2 + 1/4 + 1/7 + 1/11 + ............................ <= 2*pi
Prove that
1 + 1/2 + 1/4 + 1/7 + 1/11 + ............................ <= 2*pi
T(n) = \frac{2}{2 + n(n-1)}
Please help!!
any genius out there?
The question is
Prove that
1 + 1/2 + 1/4 + 1/7 + 1/11 + ............................ <= 2*pi
It is a very weak inequality.
\sum_{n=1}^{\infty} \frac{2}{2+n(n-1)} < 2 \left(1+ \sum_{n=2}^{\infty} \frac{1}{n(n-1)} \right) = 4< 2 \pi
I got the nth term.
But can you please tell in detail how you broke the sum in to that inequality. I am weak in this.
Thanks alot
so this should be the inequality according to your logic,
\sum_{n=1}^{\infty}{}\frac{2}{2+n(n-1)} < 2\left(\sum_{n=2}^{\infty}{} \frac{1}
How did that extra term (1) come inside the bracket?
Sorry I don't know how to copy the equation from latex editor.