If a,b,c are odd integers, prove that ax2 + bx + c = 0 does not have a rational
number solution.
Please show the procedure......
-
UP 0 DOWN 0 0 1
1 Answers
SANDIPAN CHAKRABORTY
·2010-11-20 10:03:19
check
http://www.targetiit.com/iit-jee-forum/posts/quad-14741.html
2) let the roos be p/q and r/s
then the quadratic become s
(x-p/q)(x-r/s)=0
comparing this with ax2+bx+c we get
qs=a -(ps+rq)=b and pr=c
this means q,s should be odd because their product is an odd integer a.
even p,r should be odd in a similar way
this mean s ps+rq will be evn .. but this is equal to -b whihc is an even integer..
hence a contradictoon..