Algebra - pure doubting...nothing else

71

Vivek @ Born this Way ·2011-03-24 21:33:03

I'm too getting -4/3 . The book may be wrong.

Did you do it by factorisation? If yes then post that solution please.

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kunl ·2011-03-24 21:50:34

factorizing method se bhi kiya simply write 3^3-x as 3^3/3^x and u will get a quadratic in 3^x so we factorize as (3^x-3)(3^x-9)
and clearly denominator is 3^3-3^3x/2 now simply cancel 3^x/2 -3 and put x=2 giving -24

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71

Vivek @ Born this Way ·2011-03-24 21:54:24

Thanks!

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Abhisek ·2011-03-24 23:15:11

I also got -4/3... [4]

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1

Ricky ·2011-03-24 23:17:30

@Kunl , this is in response to your doubt in my chatbox .

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kunl ·2011-03-24 23:47:57

thanx ricky

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shubhi gupta ·2011-03-25 14:39:35

I'm too getting -4/3 as a answer. it is correct!!! dude

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36

rahul ·2011-03-25 14:57:30

can someone post the solution by factorisation method?

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kunl ·2011-03-25 21:00:31

simply write 3^3-x as 3^3/3^x and u will get a quadratic in 3^x so we factorize as (3^x-3)(3^x-9)
and clearly denominator is 3^3-3^3x/2 now simply cancel 3^x/2 -3 and put x=2 giving -24

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