(B)
- Himanshu Giria i used a shortcut method by putting a equ n whose ruts are 2 and 2^2=4 as x^2-6x+8 =0Upvote·0· Reply ·2014-04-17 20:20:04
If one root of the equation ax2+bx+c=0 is the square of the other, then a(c-b)3=cX, where X is
(a) a3+b3
(b) (a-b)3
(c) a3-b3
(d) N.O.T
Please show the method ..
(B)