quadratic eqn

if the eqn ax^2+2bx-3c=0 has non real roots and 3c/4<(a+b),then c is always --------

2 Answers

This is a good question....

f(2) = 4a+4b-3c = 4(a+b-3c/4) which is given to be >0

hence for no real roots, f(x) > 0 for all x..

Hence f(0) > 0
hence -c>0
hence c<0

Corrected after sankara's post :)

sir u mistyped dat c>0,but under the condn of f(x)>0,c shud be <0

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