Quadratic Equation question

The expr. boils down to :

(x²+15x+44)(x²+15x+56)+20

Now take x²+15 = t

(t+44)(t+56)+20

t²+100t+56*44+20

Now factorise the expr. and put back value of t ... and find the value

[(x+4)(x+11)][(x+7)(x+8)]+20=0
(x²+15x+44)((x²+15x+56)+20=0
take (x²+15x+44)=t
t(t+12)+20=0
t²+12t+20=0
t=-10 or -2
put (x²+15x+44)=-10 and (x²+15x+44)=-2 sepatrately to get the answer

reek,taking the whole part (x2+15x+44) as t will be more sensible for calculation simplification,wont it?[1]

I think Arka Halder's process is shorter ... so follow that Tapan ..

thanks guys,got it.

buy arihant algebra.........................