Quadratic Equation question

multliply (x+4) and (x+11);(x+7) and (x+8) separately,then u'll get x²+ 15x as common part..then simplify

The expr. boils down to :

(x²+15x+44)(x²+15x+56)+20

Now take x²+15 = t

(t+44)(t+56)+20

t²+100t+56*44+20

Now factorise the expr. and put back value of t ... and find the value

reek,taking the whole part (x2+15x+44) as t will be more sensible for calculation simplification,wont it?[1]

I think Arka Halder's process is shorter ... so follow that Tapan ..

thanks guys,got it.

well guys

i hav been practisisng algebra frm TMH nd A DAS GUPTA....

do i need any other book as well??