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if x = 2 + 2^2/3 + 2^1/3 , then the value of x^3 -6x^2 +6x is ---???
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2 Answers
qwerty
·2010-01-13 20:24:38
x= 2+ 22/3+21/3
(x-2)3= (22/3+21/3)3
x3-6x2+12x-8 = (22/3)3 +3(22/3)2(21/3) + 3(21/3)2(22/3) +( 21/3)3
x3-6x2+12x-8 = 4 + 2 + 3(22/3)(21/3) [22/3+21/3]
x3-6x2+12x-8 = 6 + (3)(2) (x-2)
x3-6x2+12x-8 = 6+6x - 12
x3-6x2+12x - 6x = -6+8 = 2
x3-6x2+6x = 2