Sum of roots =0→-b / a =0;
therefore m=
(A)(a-b)/(a+b)
If the roots of the equation x2-bxax-c=m-1m+1 are equal but opposite in sign, then the value of of m will be
(a) a-ba+b
(b) b-aa+b
(c) a+ba-b
(d) a+bb-a
Brahmastra, Quadratic Equations Q No. 10.
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