1divide through out by (1-x)2 to get
a(\frac{x}{1-x})^{2}+b(\frac{x}{1-x})+c=0
you know for sure that the the solutions for this are
\frac{x}{1-x}=\alpha
and
\frac{x}{1-x}=\beta
now x= \frac{\alpha }{1+\alpha } , \frac{\beta }{1+\beta }
cheers!!
If α and β are the roots of the equation ax2+bx+c=0, then the roots of the equation ax2-bx(x-1)+c(x-1)2=0 are......
PLEASE GUYS GIVE THE WHOLE SOLUTION......
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3 Answers
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1thnx....bro i did the same but just divided it by (x-1)2 so i was getting the equation with -b....