anyone??
Let f(x)=x2+bx+c,where b,c\in R . If f(x) is a factor of both x4+6x2+25 and 3x4+4x2+28x+5 , then the least value of f(x) is
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7 Answers
Lokesh Verma
·2009-03-27 06:48:32
(x2+5)2-4x2 = (x2+5-2x)(x2+5+2x)
both cannot be factorized further
check which of the two is a factor of the other polynomial!
Hari Shankar
·2009-03-27 07:09:19
Another line of thought:
Let P(x) = x4+6x2+25 and Q(x) = 3x4+4x2+28x+5
If f(x) divides both P(x) and Q(x),
it must divide 3P(x) - Q(x) = 14(x2+2x+5)
So, f(x)≡x2+2x+5 = (x+1)2+4 ≥4
Subash
·2009-03-27 07:27:17
prophet sirs posts can be automatically pinked
every post shows so much proficiency :)