quadratics

1. If α,β are the roots of x2+px+q=0 then express α5+β5 in terms of p and q.

2. \left|\left|x-1 \right|-x \right| \leq 4

8 Answers

21
Shubhodip ·

a^5 + b^5 = (a2+ b2)(a3+b3) - a2b2(a+b)

1
paresh baruah ·

how would u do it for α9+β9

1708
man111 singh ·

\mathbf{\alpha^9+\beta^9=(\alpha^3)^3+(\beta^3)^3=\left(\alpha^3+\beta^3\right)^3-3.\alpha^3.\beta^3\left(\alpha^3+\beta^3\right)}$\\\\ $\mathbf{=\left\{(\alpha+\beta)^3-3\alpha.\beta(\alpha+\beta)\right\}-3(\alpha.\beta)^3.\left\{(\alpha+\beta)^3-3\alpha.\beta(\alpha+\beta)\right\}}$

1
paresh baruah ·

Is there any standard way for solving these type of questions of αn+βn

1708
man111 singh ·

$\textbf{For Second $\mathbf{x\geq-\frac{3}{2}\Leftrightarrow x\in\left\[\frac{-3}{2},\infty \right\)$}}$

21
Arnab Kundu ·

2. case 1
lets consider x as +ve
so, |x|=x
|x-1-x|≤4
it has no solution...............
case 2
lets consider x as -ve
so, |x|=-x
|-x-1-x|≤4
0r, |1-2x|≤4

now,
case 1 under case 2
let 1-2x≥0

so, 1-2x≤4
or, 2x-1≥4
or, x≥5/2

case 2 under case 2
let 1-2x<0

so, 2x-1≤4
or, x≤5/2

the ans is x either ≥2.5 or ≤2.5

1
samagra Kr ·

use this:
if Sn=αn+βn
;
then Sn+2+ pSn+1+rSn=0

62
Lokesh Verma ·

From the graph, it is obvious that the answer is x>=-1.5

*I have used a graph plotter but used it only to plot the most elementary graphs ... of |x-1| and of x... I hpe you all dont try and use graph plotters as far as possible...

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