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If a, b, c are in A.P.
p, q, r are in H.P.
and ap, bq, cr are in G.P.

then(p/r)+(r/p) is equal to

(A) (a/c)+(c/a)

(B) (a/c)-(c/a)

(C) (b/q)+(q/b)

(D) (b/q)-(q/b)

33 Answers

11
Mani Pal Singh ·

B nahin hai kya
(-5,8)`

11
Mani Pal Singh ·

arrey in rolley theorem
u first have to find the function

integrating the expression above and putting the values and further solving u will arrive at that result
solve the equations and in the end check the answer[1]

1
°ღ•๓яυΠ·

difrntial equation
y'=y/x + φ(x/y)

d solutin for this is
y=x/(log!cx!)

here ! ! denote mod

so φ(x/y) =??

11
Mani Pal Singh ·

put y/x =t

dy/dx=t+xdt/dx

we get

t+xdt/dx=t+φ(1/t)

xdt/dx=φ(1/t)

dx/x=dt/φ(1/t)

integrating on both sides

logcx=dt/φ(1/t)

we know that dt=dy/x-ydx/x2

φ(x/y)=dy/x-ydx/x2(1/logcx)

now comparing both the equations we get

[dy/x-ydx/x2]/φ(x/y)=x/y

φ(x/y)=lnx/y

1
°ღ•๓яυΠ·

integrating on both sides

logcx=dt/φ(1/t)

dt=dy/x-tdx/x

yahn wer did u integrate d othr side ??

1
°ღ•๓яυΠ·

sum one help......

even that roolles wala...........plez gimem ful sol m gettin stcuk in middle

11
Mani Pal Singh ·

oh meri maa
aage aapne aap kar le na wahan par dt ki value daal de jo last step mein likhi hui hai

fir aage nikaal le

roole waale mein ur options r not clear
give me visible options then i will tell

1
°ღ•๓яυΠ·

(A) b = 8, c =--5 (B) b = -5, c = 8
(C) b = 5, c =-8 (D) b = -5, c =-8

1
°ღ•๓яυΠ·

woh dibbe kcuh ni hai

1
°ღ•๓яυΠ·

abhirup try this plez

1
°ღ•๓яυΠ·

haan m,ethod bata na plezzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

aab hawa mein mat bata ....steps likh plez wta ur tellin 2 diff n int again mere ko ni smajh ra ...aab bata de bhai :P

11
Mani Pal Singh ·

arrey
f(1)=f(2)
baaki options se check kar le

1
°ღ•๓яυΠ·

toh
f(2)-f(1)/(2-1) =f'(4/3)

yeh ni karna kya

11
Mani Pal Singh ·

arrey yahan pe saari properties likh rolle theorem ki
then we will proceed

1
°ღ•๓яυΠ·

chode

yeh kafi hai

woh int wala kar
options are

-y^2/x^2

y^2/x^2

-x^2/y^2

x^2/y^2

11
Mani Pal Singh ·

edited that post and look at it carefully

1
°ღ•๓яυΠ·

haan sahi hai bt tune last srep wrng kara hai

neways
tussi gr8 jo ji thanks

13
Двҥїяuρ now in medical c ·

is it
(A) (a/c)+(c/a)

1
°ღ•๓яυΠ·

teri method post kar

11
Mani Pal Singh ·

arrey isse integrate kar ke naya function nikaal liya
fir uss mein values daal di

aur kya?

1
°ღ•๓яυΠ·

arey kya kara...... ??

wat i did was
f(2)-f(1)/(2-1)=f'(4/3)

??

11
Mani Pal Singh ·

i am getting

-14b-4c=15
check whether it matches any option

1
°ღ•๓яυΠ·

getting a diffrnt answer ova here

1
°ღ•๓яυΠ·

Rolle’s Theorem holds for the function f(x) = x3 + bx2 + cx, 1 <= x <=2 at the point the value of b and c are
(A) b = 8, c = -5 (B) b = 5, c = 8
(C) b = 5, c =-8 (D) b = 5, c =-8

her itz cube n squre n all

13
Двҥїяuρ now in medical c ·

so...
2p=p-q

p+q=0

1
°ღ•๓яυΠ·

haan bhai............ bt answr alag diey hai so confirmation ke liye dala :P

11
Mani Pal Singh ·

CHECK THE L.H.L
p[1+1-h]+q[1-h-1]

=>p-q=0

checking RHL u get 2p=0

1
°ღ•๓яυΠ·

yeah meh gettin d same answer given is diffrnt i mean itz a

13
Двҥїяuρ now in medical c ·

B) p + q = 0

1
°ღ•๓яυΠ·

The function f(x) = p[x + 1] + q[x – 1], where [x] is the greatest integer function is continuous at x = 1, if
(A) p – q = 0 (B) p + q = 0
(C) p = 0 (D) q = 0

meko aara hai bt answer given is diffrnt

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