quiet InSane

evaluate-

\sqrt{2011+2007\sqrt{2012+2008\sqrt{2013+2009\sqrt{2014+.........\infty}}}}

8 Answers

1
TZS 23 ·

you can take A=2011+2007 then subsequently other will be A+2 and so on
A√A+2√A+4√A+6...∞

if anyone knows how to solve this further can do it

but i dont know if this method is correct or not....

1
Ricky ·

341
Hari Shankar ·

this is a generalisation of Ramanujan's problem.

1
student ·

i will be interested to know hoe gallardo has solved that recurrence

1
Che ·

ya as prophet sir said its generalisation of Ramanujan's problem.

actually prob which ramanujan posted in Journal of Indian Mathematical Society was this

a variant of prob asked

but no one cud solve it in stipulated time of six months !

then he only gave teh soln.

1
student ·

@MI5 u know how to solve that recurrence ?

1
Che ·

ya but let Ricky ans that......i dunno why he isnt answering ;)

1
Ricky ·

Solution of f ( x ) ---

1 > Observe that , f ( x ) must be a polynomial of first degree , as in other cases , the powers of x

in f ( x ) won't match on L . H . S and on R . H . S .

So , f ( x ) = c x + b

Again , f ( 0 ) = n + a

So , b = n + a

So , f ( x ) = c x + n + a .

Now , plug this f ( x ) in the recurrence relation , from where c comes out to be 1 .

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