i knew this will happen...
i did one of them today
since, a/b = c/d
=> a/c = b/d => (a + c)/c = (b + d)/d => (a + c)/(b + d) = c/d = a/b
thus, a/b = c/d = (a + c)/(b + d) proved...
Please proof some of these
If,
a/b = c/d then prove that,
>> a/b = c/d = (a + c)/(b + d)
>> a/b = c/d = √(ac/bd)
>> a/b = c/d = (ab + cd)/(b2 + d2)
without, assuming that a/b = c/d = k and then putting the values of a,b please...!!
i knew this will happen...
i did one of them today
since, a/b = c/d
=> a/c = b/d => (a + c)/c = (b + d)/d => (a + c)/(b + d) = c/d = a/b
thus, a/b = c/d = (a + c)/(b + d) proved...
here r the other two....
a/b =√a/b x √ a/b
=√a/b x √c/d [as a/b = c/d]
= √ac / √bd
=√(ac/bd)
Again,
a/b = c/d
i.e. ad = bc
i.e. ad2=bcd
i.e. ad2 + ab2 =bcd + ab2
i.e. a (b2 + d2) = b (ab+cd)
i.e. a/b = (ab + cd)/ (b2 + d2)
i.e a/b = c/d = (ab + cd)/ (b2 + d2)