11
2740
= (24 + 3)40
= 12k1 + 340
= 12k1 + (35)8
= 12k1 + 2438
= 12k1 + (240 + 3)8
= 12k1 + 12k2 + 38
= 12k3 + (34)2
= 12k3 + 812
= 12k3 + (72 + 9)2
= 12k3 + 12k4 + 92
= 12k + 81
Hence,
remainder of 2740 / 12 = remainder of (12k + 81) / 12 = 9
1http://targetiit.com/iit_jee_articles/remainder_of_division_an_interaction_41.html
yeh dekh lo u'll get ur answer
1hey how did you guess that?!! i mean how did you get that it was going to happen this way ?
like first 24+3 (that's fine i too did it)
but 243 and then 240+3 was something which would not have striken me if i were in the examination hall
11You have to split it in such a way that you get 12p + something.Then continu the process until that something is less than 12.Then this is your ans.
Usually it's better you try to make that something=1 or 10n(if possible) so that your work is simplified.