1 Answers
Ketan Chandak
·2012-04-20 20:20:07
note that 201120112011 is divisible by 7...
so the given expression can be written as
201120112011 x 102005+201120112011 x 101999+201120112011 x 101993..........+201120112011 x 104+2011...
all the terms in the given expression are divisible by 7 except the last term....
so remainder is 2011 mod 7 which is 2...