remainders!!!

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A sequence is obtained by deleting all the perfect squares from set of natural numbers . Find the remainder when 2003rd term of new sequence is divided by 2048 ??

#Mathematics #Algebra

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4 Answers

21

eragon24 _Retired ·2010-01-03 07:03:02

There are 44 perfect squares between 1 and 2003 and after removing all the perfect squares from1² to 44² we see tat 2003rd term of this new sequence becomes 2047(i.e 2003 +44) But since 2025 is a perfect square (which is 45²) so it should also be removed .... so the after removing 2025 from teh seq. the 2003rd terms becomes 2048.

hence remainder 0

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Avinava Datta ·2010-01-04 01:29:25

thanx!!!

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49

Subhomoy Bakshi ·2010-01-04 03:30:47

ingenious......geniunely genius!!!!!!!`[1]`[4]'[5]`

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eureka123 ·2010-01-14 19:46:18

i couldnt understand eragon's explaiantion..can anyone explain in diff way ??

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Your Answer

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