A sequence is obtained by deleting all the perfect squares from set of natural numbers . Find the remainder when 2003rd term of new sequence is divided by 2048 ??
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4 Answers
21There are 44 perfect squares between 1 and 2003 and after removing all the perfect squares from12 to 442 we see tat 2003rd term of this new sequence becomes 2047(i.e 2003 +44) But since 2025 is a perfect square (which is 452) so it should also be removed .... so the after removing 2025 from teh seq. the 2003rd terms becomes 2048.
hence remainder 0
24i couldnt understand eragon's explaiantion..can anyone explain in diff way ??