then assuming we deal with one paise each
suppose the no. of paise is x
then x can have 100 values (0to 99)
among these the only possible cases (w.r.t question are)
x=0to 10 or 90 to 99 = 20 values
hence probability=20/100=1/5
3)a sum of money is rounded off to d nearest rupee d rob that d roundd off error is at most 10 paise is ?
depends on the definiton of rounding off.. there are 2-3 in the market place so i wud be careful on what is the definiton of rounding off!
then assuming we deal with one paise each
suppose the no. of paise is x
then x can have 100 values (0to 99)
among these the only possible cases (w.r.t question are)
x=0to 10 or 90 to 99 = 20 values
hence probability=20/100=1/5
see there ar ecases..
if u remmber rounding
1.5=2 and 2.5 is also 2
so that is one definiton
there is another definiton that says 1.5=2 and 2.5=3
but i think this problem is aobut solving it using the second definiton (evn though 1 is the more correct way!)
Rohan: will 1.06 give 1.1 or 1?
i think it should be 0,1,2,3,4,5,96,97,98,99 which will round of to the integer values..
hmm.. yeah it does
bcos 1.95 will get aprroximated to 2 in one case
and it will get approximated to 1.9 in another..!!
So the answer will vary to 11/100 or 10/100
I think the q is that w/e be the sum of money, it is being rounded off to nearest integer. What is the prob of the such that rounding off error is atmost 10 paise...