4 Answers
souradeepmajumde majumder
·2010-12-07 05:24:47
NO POSITIVE REAL ROOTS.................
MAX 4 NEGATIVE REAL ROOTS. MINIMUM ZERO COMPLEX ROOT......... MAXIMUM 4 COMPLEX ROOTS...........
Tush Watts
·2010-12-07 23:45:13
Dividing both sides by x2 , we get
x^{2}\ +\ x\ +\ 1\ +\ \frac{1}{x}\ +\ \frac{1}{x^{2}}\ =\ 0
Now\ put\ (x\ +\ \frac{1}{x})\ =\ y
We \ get\ (y^{2}\ +\ y\ -\ 1 ) \ =\ 0
Asish Mahapatra
·2010-12-08 17:43:04
alternatively using formula for GP,
it is x5-1x-1 = 0
i.e. x5-1 = 0 and x ≠1
hence it is fifth roots of unity excluding 1
sahil jain
·2010-12-08 20:58:28
all the roots are complex ,,well done tush ,,,,,, its the correct method