ROOTS

BITSAT 2015 Papers › Algebra questions › ROOTS

LETA,B,C Îµ R SUCH THAT 4A+2B+C=0 AND AB>0 THEN EQUATION AX²+BX+C=0 HAS WHICH ROOTS REAL,COMPLEX

#Mathematics #Algebra

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7 Answers

1

skygirl ·2008-11-25 08:18:55

x=+2 is a root... which is obviously real...

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1

skygirl ·2008-11-25 08:22:03

x=-1 is also a root.. which is also real..

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ith_power ·2008-11-25 08:50:30

how come x=-1?????

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62

Lokesh Verma ·2008-11-25 08:51:44

4A+2B+C=0
put C= -(4A+2B)

AX²+BX-(4A+2B)=0

A(X²-4) + B(X-2) = 0
A(X-2)(X+2) + B(X-2) = 0
(X-2){ A(X+2) + B } = 0

X=2 is one root

X=-2+B/A is another root..

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62

Lokesh Verma ·2008-11-25 08:52:28

u are right ith power..

-1 is not!

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Lokesh Verma ·2008-11-25 08:53:26

sum of the roots is B/A

since AB is +ve B/A is positive..

so the roots are real!

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skygirl ·2008-11-25 18:41:22

no -1 is not...
i got it by mistake...

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