Find three-digit numbers that are divisible by 5 as well as 9 and whose consecutive digits are in AP.
Pls tell which will be the best way to proceed..no need to post the solution.
-
UP 0 DOWN 0 0 2
2 Answers
11Let the hundreds place be a + r
let the tens place be a
let the units place be a - r
1take 100s place as 3a - r
10s as 3a
units 3a + r
a, r are integers
1 ≤ all of them ≤ 9
r = 0 doesn't satisfy, so all digits are distinct, that means the 10s digit can't be 9
so 3a = 3 or 6
and 3a + r = 0 or 5
.
.
.
Answer : 135, 765 and 630
