series------

1)

1 + \frac{(1.3) }{6}+ \frac{(1.3.5)}{6.8} +..............

2)\frac{2}{1!} + \frac{6}{2!} + \frac{12}{3!} + \frac{20}{4!} + .................

find the sum

7 Answers

62
Lokesh Verma ·

kaustab.. i have no idea of where 6 came in the deno from in 1) (I hope prophet or kaymant or bipin sir help us here!)

the second sum is

\\\sum{\frac{r(r+1)}{r!}}=\sum{\frac{r^2-r+2r}{r!}}=\sum{\frac{r(r-1)+2r}{r!}} \\=\sum{\frac{r(r-1)}{r!}}+\sum{\frac{2r}{r!}}

Now try to finish this off from here [1]

1
Kaustab Sarkar ·

thanks

1
akari ·

q1
(1-x)^{-\frac{1}{2}}=1+\frac{1}{1!}(\frac{x}{2}) +(\frac{x}{2})^2[ \frac{1.3}{2!}+\frac{1.3.5}{3!}(\frac{x}{2})+........\infty] \\ \\ \int_{0}^{1}{\frac{dx}{\sqrt{1-x}}}=1+\frac{1}{2.2!}+\frac{1}{2^2}(S-1) \\ \\ \\ \boxed{S=4}

62
Lokesh Verma ·

oh sorry i was answering the 2nd one again :P

1
Kaustab Sarkar ·

thanks akari for 1st 1

1
b_k_dubey ·

too good akari.... brilliant solution

1
akari ·

thanks sir :)

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