x=4 doesnt satisfy.
x=2^{\sqrt{2}}
9 Answers
Aditya Bhutra
·2012-03-27 10:58:39
rearrange the equation as
log24x =log2x . log22x
now let log2x =t
thus ,
2+t =t(1+t)
t2=2
t=±√2
x = 2±√2
mohit_ sharma
·2012-03-27 20:17:23
but please explain how you got the statement log24x =log2x . log22x
Ketan Chandak
·2012-03-27 22:46:06
@mohit....
by inverting the denominator and numerator on both sides we get the above result...
blueivy
·2012-03-29 11:16:43
You can simply convert log2x as logx /log2
so the expression will be quadratic in terms of log x
i.e.
log2 = 1
logx(logx+log2) (2log2 + logx)
you know how to solve further