simple problem

Find solution set of
logx2 . log2x2 =log4x2

9 Answers

71
Vivek @ Born this Way ·

-

11
Sambit Senapati ·

x=4 doesnt satisfy.
x=2^{\sqrt{2}}

21
mohit_ sharma ·

ans given is (2-√2,2√2)

262
Aditya Bhutra ·

rearrange the equation as

log24x =log2x . log22x

now let log2x =t

thus ,
2+t =t(1+t)

t2=2

t=±√2

x = 2±√2

21
mohit_ sharma ·

thanks Aditya

21
mohit_ sharma ·

but please explain how you got the statement log24x =log2x . log22x

1057
Ketan Chandak ·

@mohit....

by inverting the denominator and numerator on both sides we get the above result...

262
Aditya Bhutra ·

using logax = 1logxa

1
blueivy ·

You can simply convert log2x as logx /log2
so the expression will be quadratic in terms of log x
i.e.
log2 = 1
logx(logx+log2) (2log2 + logx)

you know how to solve further

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