1that is a simple one
the eqn will be of d form
1/2[(a-b)2 +(b-c)2+(c-a)2]
n then it can b easily solved
4 Answers
62The first equaiton is of the form (2x)^2+(5y)^2+(3z)^2-(2x)(5y)-(2x)(3z)-(5y)(3z)=0
Hence: (2x-5y)^2+(5y-3z)^2+(3z-2x)^2=0
Now It is a piece of cake..
as 2x=5y=3z=k
Then k/2+k/3+k/5=5
So k(31/30)=5
K= 150/31
x=75/31, y=30/31 and z=50/31
162yes...
but you should try to expand (a-b)2+(b-c)2+(c-a)2 and see what happens..