applying componendo dividendo:
\frac{2x^3+9x^2+27x+27}{x^2+3x+3} = 2x+3
2x^3+9x^2+27x+27 = 2x^3+9x^2+15x+9
12x=-18, x=-3/2
two other unreal solutions would be x→∞ and x→ -∞
Not for >12th
Solve the equation:
\frac{x^3}{x^3 + 27+9x(x+3)} = \frac{x-3}{x+6}
applying componendo dividendo:
\frac{2x^3+9x^2+27x+27}{x^2+3x+3} = 2x+3
2x^3+9x^2+27x+27 = 2x^3+9x^2+15x+9
12x=-18, x=-3/2
two other unreal solutions would be x→∞ and x→ -∞
coz it is easy , so i thought it's good for engaging 11th class students