for first one answer is (1-(1/2)7)8
for last one answer is (1/2)63
if the squares of a 8x8 chess board are painted either red or black at random
1)the probability taht not all squares in any column are allternating in color
3)the probability that all the squares in any column are of same color and alternating color in any row
plz help in these q......i m not able to get any head or tail of it[7]
just tell me one thing, can the colors in the rows be alternating or is thee any restriction on that also ?
see for the first one colors in the rows can be alternating......nothing metioned in the q on taht front..........
1)the probability taht not all squares in any column are allternating in color
The number of ways in which all squares in a column are alternating is 2
while the no of ways to fill one column is 28
Hence prob is 2/28
but you want none fo the 8 columns to be alternating
hence (1-1/27)8
3)the probability that all the squares in any column are of same color and alternating color in any row
The number of ways to do this is 2
the number of ways to fill the whole chess board is 264
so the answer is 2/264 = 1/263
oh yeah thanx :)thanx a lot....the problem seems too easy once u get the soln.. :P
actually i din see ur post for 3rd soln....was talking abt that only........thanx