special for aashish.... let him do first....

JEE Advanced 2015 Discussion Forum › Algebra questions › special for aashish.... let him do first....

f((x+y)/2)= A.M of f(x) and f(y)..

if f'(0) exists and f'(0) = -1 and f(0) = 1

then f(2) =?

#Mathematics #Algebra

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7 Answers

1

sahil jain ·2010-10-04 00:07:35

ans. is -1...

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nihal raj ·2010-10-04 00:21:37

answer should be -1..

my approach.....

f(x) should be -x + 1 so f(1) = 0 and

2[f(1)] -1= f(2)

f(2)=-1

.....
am i right??

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Aashish Jindal ·2010-10-04 00:34:44

nihal,i have done it before ur posting......
someone had writteen in instant chat......

it is the simplest que. of functional inequality........

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sahil jain ·2010-10-04 04:34:35

oye nihal ,hw cn u say that fx =-x+1 without any calculation?

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nihal raj ·2010-10-04 05:31:43

i don't think that any other eq. satisfies above conditions.so hit and trial worked neways use functional inequality........

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sahil jain ·2010-10-04 05:43:56

dont go with hit n trials ,,,,,,,,,too risky,,,,,,, dere is proper method to solve it,...........

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nihal raj ·2010-10-04 05:49:26

it is risky ... it sometime works.....

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