mean = Σfxi /Σi
fx =1 here
so its simply N/N =1
If the valences 1,1/2,1/3,1/4....occur at frequency 1,2,3,4,5.......,n in a distribution then the mean is :
a. 1
b. n
c. 1/n
4.NONE
17 views but not even i single reply.......koi to solve kardo
wat is the relation b/w median deviation and standard deviation
m.d <= s.d
or
m.d< s.d
proof
m.d = Σ a /N where a,b,c... = mod of deviation frm mean
s.d =√Σ a2/N
now for N=1 sd=md=0
N=2 sd=md (as a=b always )
for N>2 assume
sd >= md
→ N Σa2 ≥( Σa)2
→ Σ (a-b)2≥0
which is true always