1
Honey Arora
·Jul 8 '09 at 7:01
how to solve this prob???
9
Celestine preetham
·Jul 8 '09 at 7:50
honey
n2 = (n+1)(n+2) + (n+2) - 4(n+1)
now its solvable
1
archana anand
·Jul 8 '09 at 19:24
ans is
2/3[22n+1((n-1)/(n+1))+1]
after breakin the summation as in #4 and then solvin
is it correct???
11
Tarun Kumar Yadav
·Jul 8 '09 at 21:11
the correct answer is
Sn = 2/3{1+22n+1((n-1)/(n+2))}
9
Celestine preetham
·Jul 8 '09 at 21:14
i think it shud be
see putting n=1 yields 2/3 put n=2 and also crosscheck ull know if its right for pucca
1
archana anand
·Jul 8 '09 at 21:16
wats the difference between #6 and#7.
9
Celestine preetham
·Jul 8 '09 at 21:23
#7 is correct for n=2 also
archana check ur s
1
archana anand
·Jul 8 '09 at 22:17
oh yes sorry got mah mistake
1
rahul1993 Duggal
·Aug 6 '09 at 5:10
can someone please post the complete solution
341
Hari Shankar
·Aug 6 '09 at 8:35
http://www.goiit.com/posts/list/algebra-find-summation-upto-n-terms-if-t-n-n-2-4-n-n-1-n-2-913244.htm#944176