Summation Problem

If T_n = \frac{4^n n^2}{(n+1)(n+2)}

Find Sn where S_n = \sum_{i=1}^n T_n

11 Answers

1
Honey Arora ·

how to solve this prob???

9
Celestine preetham ·

must try for juniors

9
Celestine preetham ·

honey

n2 = (n+1)(n+2) + (n+2) - 4(n+1)

now its solvable

1
archana anand ·

ans is
2/3[22n+1((n-1)/(n+1))+1]
after breakin the summation as in #4 and then solvin
is it correct???

11
Tarun Kumar Yadav ·

the correct answer is

Sn = 2/3{1+22n+1((n-1)/(n+2))}

9
Celestine preetham ·

i think it shud be

see putting n=1 yields 2/3 put n=2 and also crosscheck ull know if its right for pucca

1
archana anand ·

wats the difference between #6 and#7.

9
Celestine preetham ·

#7 is correct for n=2 also

archana check ur s

1
archana anand ·

oh yes sorry got mah mistake

1
rahul1993 Duggal ·

can someone please post the complete solution

341
Hari Shankar ·

http://www.goiit.com/posts/list/algebra-find-summation-upto-n-terms-if-t-n-n-2-4-n-n-1-n-2-913244.htm#944176

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