341\frac{(4r-1)5^r}{r^2+r} = \frac{5^{r+1}}{r+1} - \frac{5^{r}}{r}
But sum to infinite terms doesnt look finite to me
nth term of a series can be written as ar= f(r) - f(r-1), then
Sn=\sum_{r=1}^{n}{a_{r}} =f(n) - f(0)
and S∞=Sn , then
Value of \sum_{r=1}^{infinity}{(4r-1)5^{r}/(r^{^{2}}+r)}
is??
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6 Answers
341
1I mean even am getting Infinite series..... but there is some answer! So please solve!