1ya but still it has a minimum value nishant....
i think its min value = 0?
isnt it??
If x = z√(1 - y2) + y√(1 - z2), find the minimum value of (x + y + z)(x - y + z)(x + y - z)(-x + y + z).
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8 Answers
1No!
U can take....... (sin-1 x = sin-1 z + sin-1 y)
Now, can u solve it?
But, I rather had a much simpler & algebrical solution.......
It wud be gud if u an reach the answer through Trigo. also!
62i can think of a nice(?) solution
take x=sin A , y = sin B
multiply both sides by k to get
z=sin A cos B + sin B cos A
Which reminds me of a=bcosC + c cos B
which i can get by multiplying by 2R
so 2Rz = c = a cos B + b cos A
The Thing that we have to find is closely related to the area of a triangle.. infact the square of it
Now can someone clear the question from the table ;)
62i discussed this one with nikhil yesterday..
The question has a small error.. it is not to minimize this one but to find the value of it! [1]
162are u sure nikhil?
I would not jump to that conclusion so fast..
bcos the LHS here is not exactly sin a cos B + sin B cos A
but sin a |cos B| + sin B |cos A|
so you need to think slightly more before concluding what you have ;)
106but sir, if we fix y and z such that y=z=0 then x=0.. so the value of the expression becomes zero
(I am not saying that the min. value is not zero or zero)
Still thinking