Very Interesting

Let a,b,c be three distinct real numbers such that the expression ax2+bx+c,
bx2+cx+a, and
cx2+ ax+b
is positive for each x belongs to R
and let α =(bc+ca+ab)/(a2+b2+c2)

Then
(a) α<4
(b) α<1
(c) α>1/4
(d) α>1

3 Answers

383
Soumyabrata Mondal ·

(c) α>1/4

383
Soumyabrata Mondal ·

for (i) eq. b2-4ac>0
for (ii) eq. c2-4ac>0
for (iii) eq. a2-4bc>0

now combine all..........

1357
Manish Shankar ·

Answer is C

Applying AM GM on a, b, c

i.e. a2+b22≥ab
b2+c22≥bc
c2+a22≥ca

adding the three
a2+b2+c2≥ab+bc+ca

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