very simple

very simple ones bt im stuck..
1.find minimum value of (a2+3a+1)(b2+3b+1)(c2+3c+1)/abc
2.x,y,z are +ve real no.s satisfy 4xy+6yz+8xz=9 find max value of xyz.

5 Answers

1
xYz ·

it can be written as
(a+1/a +3)(b+1/b +3)(c+1/c +3)
5*5*5.........(as a+1/a min value is 2)

3
msp ·

but this only holds when a,b,c are +ive isnt it.

11
Mani Pal Singh ·

for 2nd ques
(x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2xz

1
Philip Calvert ·

2nd one is simply AM >= GM

1
Debanjana Mukher ·

ya thanx everybody..

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