very simple

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very simple ones bt im stuck..
1.find minimum value of (a²+3a+1)(b²+3b+1)(c²+3c+1)/abc
2.x,y,z are +ve real no.s satisfy 4xy+6yz+8xz=9 find max value of xyz.

#Mathematics #Algebra

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xYz ·2009-10-12 09:43:39

it can be written as
(a+1/a +3)(b+1/b +3)(c+1/c +3)
5*5*5.........(as a+1/a min value is 2)

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msp ·2009-10-12 09:48:11

but this only holds when a,b,c are +ive isnt it.

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Mani Pal Singh ·2009-10-12 11:04:58

for 2nd ques
(x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2xz

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Philip Calvert ·2009-10-13 00:41:31

2nd one is simply AM >= GM

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Debanjana Mukher ·2009-10-16 18:04:23

ya thanx everybody..

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very simple

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