it can be written as
(a+1/a +3)(b+1/b +3)(c+1/c +3)
5*5*5.........(as a+1/a min value is 2)
very simple ones bt im stuck..
1.find minimum value of (a2+3a+1)(b2+3b+1)(c2+3c+1)/abc
2.x,y,z are +ve real no.s satisfy 4xy+6yz+8xz=9 find max value of xyz.
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5 Answers
xYz
·2009-10-12 09:43:39