see the units place will have 1,3,5,7,9
If we take 9 then there are 54 ways
Therefore total will be 54(9+3+5+7+1) = 56
Total summation will be
56 + 1056 + 10056 + 100056 +1000056
56(1+10+100+1000+10000
Therefore option c)
The sum of all 5 digit nos. formed by the digits 1,3,5,7,9 when repetetions are alowed is
a)66666600 b)6666600 c)56*11111 d) 55*11111
see the units place will have 1,3,5,7,9
If we take 9 then there are 54 ways
Therefore total will be 54(9+3+5+7+1) = 56
Total summation will be
56 + 1056 + 10056 + 100056 +1000056
56(1+10+100+1000+10000
Therefore option c)