1
Che
·2010-03-15 06:29:07
take dy/dx=p
so p2-xp+y=0
differentiat wrt x
2p.dp/dx-p-xdp/dx+p=0
dp/dx(2p-x)=0
dp/dx=0....so p=c
or
p=x/2
dy/dx=x/2
y=x2/4 + c
so that doesnt match with teh option but does satisfy
so that wasnt the only soln given...der r many more.....so thts why they may hav solved using options ? or am i rong ?
????
29
govind
·2010-03-15 10:48:51
dunno why che's answer was not there in the options..
...but if we take the case that dp/dx = 0 ..t
that means p = constant ..c
dy/ dx = c..
y = cx + d
on puuting this in the differential equation we get
y = cx - c2
and there was a similar option there in the question... : )
1
Che
·2010-03-15 10:54:20
@govind well x^2/4 is satisfying the differential eq :)
29
govind
·2010-03-15 11:03:05
Sry che.....was making a silly mistake.....anyways the problem is solved now...Thanks Che for the showing the way..how to solve it... : )