A FUNCTION PROBLEM

Suppose that , any four solutions are of the form ,

" 4 + x₁ , 4 + x₂ , 4 + x₃ , 4 + x₄ " ;

where " x₁ , x₂ , x₃ , x₄ " are constants .

Then , Given " f ( 4 + x ) = f ( 4 - x ) " ;

Hence , if " 4 + x₁ " is a solution , so is " 4 - x₁ " .

So the other four solutions must be , " 4 - x₁ . 4 - x₂ , 4 - x₃ , 4 - x₄ " .

So , sum of the roots = 4 x 8 = 32

So the ans. is - ( a ) , ( c ) , ( d ) .

hey a nice approach!!!