akin to a jee09 question

Options are (a)\frac{1}{2}\; \; \; \; (b)\frac{-1}{2}\; \; \; \; (c)\frac{-1}{2}<g'(1)<\frac{1}{2}\; \; \; \; (d)none\; of\; these

ani : chk da Que, isnt the co-eff of x^101 2 as then it gets simpler in calculation

g(fx)=x
diff both sides
g'(fx)f'x=1

fx =1 means x =?

yeah if its 2 then x = -1 in my sol abv

@archana

g(f(x))=x

g'(f(x))f'(x)=1

g'(f(x))=1/f'(x)

now we have to find the value when f(x) becomes 1
x=-1.01..... (something)

g'(1)=1/f'(-1)

g'(1)=1/125

so the answer is C

mani can u pl. show how is f(-1) = 1 ???? [7]

aakhir ye REST IN PEACE KAUN HAI ?????????

bhai i never said f(-1)=1 but something very close to -1 which is left of -1
that is the reason y i wrote (something)

in the options option is given in the interval from -1/2 to 1/2

saaala 12 ko q chood ke a gaya
dimmag ke kutte nahin chaal rahe the us waqt
bada matha maara iske saath
par attemp nahin kar paya:(