An Old problem

This question was posted by Bhatt sir about more than a year back in another forum:

Let f(x)=\sin(x^3)

Determine all n for which the n-th derivative of f(x) is non-zero at x=0.

9 Answers

1
Arshad ~Died~ ·

n= multiples of 3 i think

66
kaymant ·

No Arshad, the 6th derivative is 0.

11
Tush Watts ·

@ Anant sir
Can we do it by LEBINTZ RULE OF SUCCESSIVE DIFFERENTIATION ??

66
kaymant ·

go ahead tushar..

1
Arshad ~Died~ ·

no one till now??
sir pls give a hint....

24
eureka123 ·

lebnitz rule ????

or taylors series ??
i think it will be done by taylors series...

66
kaymant ·

A series expansion of sin(x3) will be useful.

4
UTTARA ·

3rd derivative , 9th 15th .....

n = 3 ( any odd no. )

24
eureka123 ·

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